in reply to Re: Foreach Loops
in thread Foreach Loops

And, of course, the previous line is available at $arr[$x - 1]

(unless we're talking $x == 0)

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Re^3: Foreach Loops
by Anonymous Monk on Mar 16, 2005 at 15:19 UTC
    Well, if you consider arrays to be circular, if $x == 0, then $arr[$x - 1] is the last element. Which would be just right. Unfortunally, it doesn't work the way. $arr[$#arr + 1] isn't the same as $arr[0].
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