Re^12: Why is the execution order of subexpressions undefined?

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Comment on Re^12: Why is the execution order of subexpressions undefined?

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Re^13: Why is the execution order of subexpressions undefined? by Anonymous Monk on Apr 14, 2005 at 14:26 UTC
Don't what? Write expressions? sigh Don't write expressions where the value depends on the order of evaluation when the order of evaluation isn't defined. But I guess you just don't want to understand what I write. I give up. I always though you were one of the smarter people on Perlmonks. Now I no longer think so.	[reply]
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