in reply to Re^41: Why is EO undefined? (More details!)
in thread Why is the execution order of subexpressions undefined?
Without extra syntax, separate statements means serialisation. Compound expressions permit concurrency without extra syntax.See. Right there. We're working off of a complete different set of assumptions. What in the world makes you think the above quote is true? Are you talking about a particular parallel language you haven't mentioned? (Is there a parallel/array dialect of Perl out there?) Because in the general case that statement is false, if for no other reason than it is overly general.
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Re^43: Why is EO undefined? (More details!)
by Anonymous Monk on Apr 18, 2005 at 16:15 UTC | |
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Re^43: Why is EO undefined? (More details!)
by BrowserUk (Patriarch) on Apr 18, 2005 at 19:51 UTC |