in reply to '+' to +

This one involves a bit of magic, but it does not use eval, nor does it explicitly list the four operators. 

use Math::BigFloat; $big = Math::BigFloat->bzero; 
$Problem = "12 - 5"; 
$Problem =~ /^(\d+)\s(\S)\s(\d+)$/; ($Number1, $Operator, $Number2) = 
+($1, $2, $3); 
$Answer = ($big + $Number1)->${\("(" . $Operator)}($Number2); 
print $Answer, "\n";

[download]

Replies are listed 'Best First'.
Re^2: '+' to +
by ambrus (Abbot) on May 30, 2005 at 20:54 UTC

    The same idea, except that it's a bit faster, still using only core modules. 

    use Math::Complex; $big = 0*i;
$Problem = "6 * 8";
$Problem =~ /^(\d+)\s(\S)\s(\d+)$/; ($Number1, $Operator, $Number2) = 
+($1, $2, $3);
$Answer = ($big + $Number1)->${\("(" . $Operator)}($Number2);
print $Answer, "\n";

    [download]
[reply]
[d/l]

In Section Seekers of Perl Wisdom