Re: Fastest way to get input from a filehandle

I would expect the fourth one is the slowest, since you're going out of your way to get a line. The first three are, I believe, identical.

But this is not where you should be looking for speed increases in your code. This is such a minor issue. You're over-optimizing.

Jeff japhy Pinyan, P.L., P.M., P.O.D, X.S.: Perl, regex, and perl hacker
How can we ever be the sold short or the cheated, we who for every service have long ago been overpaid? ~~ Meister Eckhart

Comment on Re: Fastest way to get input from a filehandle

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Re^2: Fastest way to get input from a filehandle by sauoq (Abbot) on Oct 29, 2005 at 16:34 UTC
I would think the 2nd would be slowest since there is an extra step of getting the right filehandle from the string... `$ perl -MO=Deparse -e 'readline(STDIN)' readline 'STDIN'; -e syntax OK` [download] Not sure when that happens though. (One time penalty?) I would expect the fourth to be about as quick as the others (after the open) as it's just dup'ing STDIN. Is it slower to store a filehandle in a lexical? (I wouldn't think so but have no real clue.) shrug Not that any of this changes the fact that it shouldn't matter to the OP. :-) -sauoq "My two cents aren't worth a dime.";	[reply] [d/l]

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Re^2: Fastest way to get input from a filehandle
by sauoq (Abbot) on Oct 29, 2005 at 16:34 UTC

I would think the 2nd would be slowest since there is an extra step of getting the right filehandle from the string...

$ perl -MO=Deparse -e 'readline(STDIN)'
readline 'STDIN';
-e syntax OK
[download]

I would expect the fourth to be about as quick as the others (after the open) as it's just dup'ing STDIN. Is it slower to store a filehandle in a lexical? (I wouldn't think so but have no real clue.)

shrug

Not that any of this changes the fact that it shouldn't matter to the OP. :-)

-sauoq
"My two cents aren't worth a dime.";

[reply]
[d/l]