in reply to Challenge: Box Blackout
Note that boards with just one piece missing are solutions (not optimal!) and so are all predecessors to a full board in a path such as you show. So, working back from boards with one empty square (each of the N*N possibilities) one can find optimal starting points (which will be a symmetric family).
If I were still teaching advanced programming, I would probably use this game.
--traveler
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Re^2: Challenge: Box Blackout
by loris (Hermit) on Jan 24, 2006 at 11:41 UTC | |
by traveler (Parson) on Jan 24, 2006 at 15:58 UTC |