in reply to caller() mystery

$ perl use strict; use warnings; use Log::Log4perl qw(:easy); Log::Log4perl->easy_init($DEBUG); sub show_call_stack { my $max_depth = 7; my $i = 1; # start on 1 to skip last function call DEBUG("--- Begin stack trace ---"); while ((my @call_details = (caller($i++))) && ($i < $max_depth)) { DEBUG( "$call_details[1] line $call_details[2] in function $call_detail +s[3]"); } DEBUG("--- End stack trace ---"); } sub foo { show_call_stack(); bar(); } sub bar { show_call_stack(); tze(); } sub tze { show_call_stack(); } # ------ main ------ foo(); __END__ 2008/09/26 12:16:35 --- Begin stack trace --- 2008/09/26 12:16:35 - line 33 in function main::foo 2008/09/26 12:16:35 --- End stack trace --- 2008/09/26 12:16:35 --- Begin stack trace --- 2008/09/26 12:16:35 - line 20 in function main::bar 2008/09/26 12:16:35 - line 33 in function main::foo 2008/09/26 12:16:35 --- End stack trace --- 2008/09/26 12:16:35 --- Begin stack trace --- 2008/09/26 12:16:35 - line 25 in function main::tze 2008/09/26 12:16:35 - line 20 in function main::bar 2008/09/26 12:16:35 - line 33 in function main::foo 2008/09/26 12:16:35 --- End stack trace --- $
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No matter how great and destructive your problems may seem now, remember, you've probably only seen the tip of them. [1]

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Re^2: caller() mystery
by rovf (Priest) on Sep 26, 2008 at 10:48 UTC

    I finally understand! (caller(0))[1,2] give me filename and line of the place where I was called from; but to see from what other subroutine I was called, I need to access (caller(1))[3]. Thanks a lot for clarification!

    -- 
    Ronald Fischer <ynnor@mm.st>