in reply to Regex bug in 5.10 (was: Using Look-ahead and Look-behind)
in thread Using Look-ahead and Look-behind

You are right, my change did not affect greediness. The bad thing is: now I don't understand why my proposed solution worked at all. Maybe someone can explain? I don't think the question is too important, but I like to use regular expressions and it bugs me a little if I cannot understand one (especially such a tiny one).

I have read the documentation you have cited and it helped, so I played around some more and tried out the following, which only exchanges "+" for "*" in your original expression, really works as one would think and therefore would be my preferred solution, at least for Perl 5.10:

$_ = "Hello"; print "$1\n" while /(?=(.+))/g;
Output:
Hello ello llo lo o

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Re^2: Regex bug in 5.10 (was: Using Look-ahead and Look-behind)
by ikegami (Patriarch) on Nov 28, 2024 at 17:00 UTC

    Note that using + instead * is not equivalent.

    $ perl -e'$_ = "Hello"; print "<$1>\n" while /(?=(.*))/g;' <Hello> <ello> <llo> <lo> <o> <> $ perl -e'$_ = "Hello"; print "<$1>\n" while /(?=(.+))/g;' <Hello> <ello> <llo> <lo> <o>