Re: Variable Removal From End of String

Your post is not really clear. Do you mean Array or String?

substr( $str, -20   )= '';   #string, removes chars
splice( @array, -20 )= ();   #array, removes scalars
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Jeroen
"We are not alone"(FZ)
Update: Avoided double numbers by using the lvalue property of these functions.

Comment on Re: Variable Removal From End of String Download Code

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Re: Re: Variable Removal From End of String by cdherold (Monk) on May 01, 2001 at 11:49 UTC
Apologies for the lack of clarity in the post (still new to this game)... I have an array ,@images, that I made into a scalar by the following method (my mistake on terming this a string if it is not) ... `$links = join(",", @img), "\n";` When I print $links out I get a list (a,b,c...etc). The size of this list is variable, but I wish to get rid of the last 20 components in every case. I tried to use the splice () option you suggested before joining @img into a scalar. I had compilation problems, however. More than likely I am doing it incorrectly ... Could you let me know? `splice( @img, -20 )= @img; $links = join(",", @img), "\n";` [download] thanks for your patience, cdherold	[reply] [d/l] [select]
(tye)Re: Variable Removal From End of String by tye (Sage) on May 01, 2001 at 19:22 UTC
`splice( @array, -20 )= (); #array, removes scalars``Can't modify splice in scalar assignment` I don't think you tested that code. splice can't be assigned to. You instead want: `splice @array, -20;` - tye (but my friends call me "Tye")	[reply] [d/l] [select]
Re: (tye)Re: Variable Removal From End of String by jeroenes (Priest) on May 01, 2001 at 21:42 UTC
Arghle.... ahum. Yes. Got carried away by substr, clearly. Thx for pointing that one out.	[reply]
Re: Re: Variable Removal From End of String by cdherold (Monk) on May 01, 2001 at 12:00 UTC
Never mind about the last post ... got it with splice(@img,-20); thanks very much for your and everyone else's help. cdherold	[reply]