Re^2: Could someone please explain this to me in newbie terms :)

To be explicit, $z = $y && $x / $y; construct assigns the value of $y to $z, not necessarily a zero unlike $z = $y ? $x / $y : 0;.

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Re^3: Could someone please explain this to me in newbie terms :) by Anonymous Monk on Aug 08, 2009 at 09:47 UTC
... when `$y` evaluates to a false truth value.	[reply] [d/l]