Re^2: Why doesn't SUPER cause dead loop here?

in reply to Re: Why doesn't SUPER cause dead loop here?
in thread Why doesn't SUPER cause dead loop here?

Let's focus on step 2

shift->SUPER::new(@_)

Here the result of shift should be son,right?

then shift->SUPER::new should still call father::new,right?

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Re^3: Why doesn't SUPER cause dead loop here? by ikegami (Patriarch) on Sep 02, 2011 at 02:52 UTC
No, `father` is not in `@father::ISA` or a descendant of the classes therein. `SUPER` relates to the class in which the code using it is compiled. It doesn't involve the invocant. By the way, what's a dead loop? Is that the same thing as an infinite loop?	[reply] [d/l] [select]
Re^4: Why doesn't SUPER cause dead loop here? by PerlOnTheWay (Monk) on Sep 02, 2011 at 03:06 UTC
Yes, I actually means infinite loop~	[reply]

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