Re: Use scalars to define a filename

Perl thinks you have a variable named $var1_.

my $fileName = "fileLocn/$var1_$var2.txt";

Change that to:

my $fileName = "fileLocn/${var1}_$var2.txt";
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Re^2: Use scalars to define a filename by akrrs7 (Acolyte) on Oct 17, 2011 at 14:16 UTC
Thanks Toolic...that fixed it.	[reply]