Re^2: How exactly does no work?

Why is it NOT fatal when I print $b; in sub a?

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Re^3: How exactly does no work? by moritz (Cardinal) on Feb 16, 2012 at 11:33 UTC
Because $a and $b are global variables, and thus don't need to be declared. Perl 6 - second systems done right	[reply]
Re^3: How exactly does no work? by choroba (Cardinal) on Feb 16, 2012 at 11:36 UTC
See sort and perlvar. `$a` and `$b` are special variables.	[reply] [d/l] [select]