Re: Re: Cropping the output of the pattern matcher

I will definitely take it under advisement and look into the modules others have developed for this porpoise,
but in the spirit of learning please advise me on using split. I am now trying your code Trantor like so:

#!/usr/local/bin/perl -w 

use strict;

my $line = "a whole lotta shakin >pattern here< goin on";

my @bits_and_pieces = split /></, $line;

print @bits_and_pieces;
[download]

Done this way the out put is the same as $line was originally:
a whole lotta shakin >pattern here< goin on
But if I use
my $line = "a whole lotta shakin ><pattern here>< goin on";
Then my output is: a whole lotta shakin pattern here goin on
The only thing that happened was my delimiters were deleted.
Would some kind soul explain why split did that.
I read perlfunc:split but I'm afraid I am no wiser.
TIA,
jg

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Re: Re: Re: Cropping the output of the pattern matcher by hopes (Friar) on Sep 24, 2001 at 05:14 UTC
It seems as the delimiters were deleted, but the print is a little tricky First, you had the string: `my $line = "a whole lotta shakin >pattern here< goin on";` [download] and you did `my @bits_and_pieces = split /></, $line;` [download] What did it make? This code "splits" the string, searching '><' as delimiter. Because of '><' is not matched in the string, in @bits_and_pieces you will have only one element, and it would be `'a whole lotta shakin >pattern here< goin on'` [download] (all the string) In the other hand, you did this `my $line = "a whole lotta shakin ><pattern here>< goin on"; my @bits_and_pieces = split /></, $line;` [download] Then, perl searches '><' in the string and splits it into an array. So @bits_and_pieces would be now `('a whole lotta shakin ','pattern here',' goin on')` [download] If you print @bits_and_pieces with `print @bits_and_pieces;` [download] is printed `'a whole lotta shakin pattern here goin on'` [download] as if the delimiters '><' where removed from the array. Hope this help Hopes	[reply] [d/l] [select]
Re: Cropping the output of the pattern matcher split by mandog (Curate) on Sep 24, 2001 at 07:28 UTC
The only thing I might add to hopes fine reply to jerrygarciuh's question about split is that changing the final print might make the point clearer..... `print "numboer of array elements==". scalar(@bits_and_pieces)."\n"; print join("\n",@bits_and_pieces);` [download]	[reply] [d/l]