But isn't %_ immune to strict in the same way and for the same reasons as $_ and @_?

C:\test>perl -cmstrict -E"say %_"
-e syntax OK
[download]

That is, they are all 3 a part of the same typeglob.

But isn't %_ immune to strict in the same way and for the same reasons as $_ and @_?

Maybe technically :) but according to the current documentation it shouldn't be, because unlike "$a" and "$b" the hash "%_" isn't used by sort or any perl feature

OTOH, perlvar, which lists $a and $b, also says these types are exempt from strict-vars

so what about %_? Makes sense to me for strict-vars to compain , its not like it requires extra chars like %{_} or ${^SNACKS}

curious http://perl5.git.perl.org/perl.git?a=search&h=HEAD&st=grep&s=%25_, http://perl5.git.perl.org/perl.git/blob?f=t/japh/abigail.t#l483

See perlvar (for 5.10) when there was a section entitled "Technical Note on the Syntax of Variable Names", which contained the paragraph:

Perl identifiers that begin with digits, control characters, or punctuation characters are exempt from the effects of the package declaration and are always forced to be in package main; they are also exempt from strict 'vars' errors.

Seems to have disappeared from later versions.

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