PearlsOfWisdom has asked for the wisdom of the Perl Monks concerning the following question:
my $myRange = $rangeEnd - $rangeStart; seek($fh,$rangeStart,0); my $currentIncrement=0; my $numberOfIncrements = $myRange / $readSz; do { $n1 = read($fh, $buf1, $readSz); # DO STUFF WITH $buf1 # $currentIncrement++; } until !defined($n1) || $n1 == 0 || $currentIncrement==$numberOfIncre +ments;
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Re: Byte ranges of binary files
by RichardK (Parson) on Jul 27, 2013 at 15:40 UTC | |
by PearlsOfWisdom (Initiate) on Jul 27, 2013 at 16:02 UTC | |
by PearlsOfWisdom (Initiate) on Jul 27, 2013 at 22:39 UTC | |
by RichardK (Parson) on Jul 28, 2013 at 10:22 UTC | |
by PearlsOfWisdom (Initiate) on Jul 28, 2013 at 16:03 UTC | |
by Anonymous Monk on Jul 28, 2013 at 20:20 UTC | |
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Re: Byte ranges of binary files
by zork42 (Monk) on Jul 28, 2013 at 05:19 UTC | |
by PearlsOfWisdom (Initiate) on Jul 28, 2013 at 08:12 UTC | |
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Re: Byte ranges of binary files
by BrowserUk (Patriarch) on Jul 27, 2013 at 15:01 UTC | |
by PearlsOfWisdom (Initiate) on Jul 27, 2013 at 15:17 UTC | |
by BrowserUk (Patriarch) on Jul 27, 2013 at 15:59 UTC | |
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Re: Byte ranges of binary files
by zork42 (Monk) on Jul 29, 2013 at 04:54 UTC |