Re: Perl compare ( numeric in void isn't numeric)

Don't understand what's wrong. Please help!

There are checklists for that , Basic debugging checklist

Work through the list, turn on diagnostics, read the more verbose error message, use Deparse to see how perl parses your code

"1,2" is not "a number" or "a string" , its "a list", its two numbers seperated by the comma operator

Comment on Re: Perl compare ( numeric in void isn't numeric)

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Re^2: Perl compare ( numeric in void isn't numeric) by waytoperl (Beadle) on Sep 26, 2014 at 04:18 UTC
"1,2" is not "a number" or "a string" , its "a list", its two numbers separated by the comma operator it's a list `my ($num1,$num2) = split (',',$number4); if ($num1 == 1 && $num2 == 2) {....` [download] above code have no warning	[reply] [d/l]
Re^3: Perl compare ( numeric in void isn't numeric) by choroba (Cardinal) on Sep 26, 2014 at 13:36 UTC
It seems $number4 is not a list, it's a string. So, use string comparison `eq` and quote the string literals: `if ($number4 eq '1,2') { # ... }` [download] لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]
Re^3: Perl compare ( numeric in void isn't numeric) by GotToBTru (Prior) on Sep 26, 2014 at 14:33 UTC
No, a scalar can not be a list. It is a string containing two digits separated by a comma. 1 Peter 4:10	[reply]