Re^2: Perl compare ( numeric in void isn't numeric)

"1,2" is not "a number" or "a string" , its "a list", its two numbers separated by the comma operator

it's a list

my ($num1,$num2) = split (',',$number4);
if ($num1 == 1 && $num2 == 2) {....
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above code have no warning

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Re^3: Perl compare ( numeric in void isn't numeric) by choroba (Cardinal) on Sep 26, 2014 at 13:36 UTC
It seems $number4 is not a list, it's a string. So, use string comparison `eq` and quote the string literals: `if ($number4 eq '1,2') { # ... }` [download] لսႽ† ᥲᥒ⚪⟊Ⴙᘓᖇ Ꮅᘓᖇ⎱ Ⴙᥲ𝇋ƙᘓᖇ	[reply] [d/l] [select]
Re^3: Perl compare ( numeric in void isn't numeric) by GotToBTru (Prior) on Sep 26, 2014 at 14:33 UTC
No, a scalar can not be a list. It is a string containing two digits separated by a comma. 1 Peter 4:10	[reply]