Re: why can't I shift a split?

Take a look at shift. It says "shift ARRAY", not "shift LIST".

Look down to the ~~next~~second paragraph where it talks about an experimental feature that's been removed. I'm guessing the version of Perl you're using is >=v5.14 and <v5.24: so it's trying to use that experimental feature but failing because "( @_ = split /,/ )" is not an array, nor does it evaluate to an arrayref.

You can try the following with your version of Perl. I don't have a version earlier the v5.30, so I get:

$ perl -MO=Deparse -e 'shift ( @_ = split /,/ )'
Experimental shift on scalar is now forbidden at -e line 1, near "/,/ 
+)
"
-e had compilation errors.
shift(@_ = split(/,/, $_, 0));
[download]

— Ken

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Re^2: why can't I shift a split? by ikegami (Patriarch) on Aug 25, 2022 at 15:42 UTC
That's an assignment, not an array. The closest valid code is `shift @{ @_ = split /,/; \@_ }` [download] There's no need to use named array, though. `shift @{[ split /,/ ]}` [download] But I'd use a list slice, as shown in my reply to the OP.	[reply] [d/l] [select]