perl -MO=Deparse,-p -e '120*312-77728+2.22772.224792222->x'
((-40288) + "\cB\x{58f4}\x{d660e9e}"->x);
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Still asking why?

2.22772.224792222 is not a number, it's "version" string, i.e. three characters whose ords are 2, 22772, and 224792222. The -> operator is called on this string which interprets it as a class name.

Good catch about the version string but I would only say The -> operator is called on this string which interprets it as a class name. It has nothing to do with version string, e.g. 42->x does the same. I think.

Yes, 42 is turned into the string "42" which is interpreted as a class name. Basically, anything that's not a reference is stringified by the arrow operator.

Update: See The Arrow Operator in perldoc.

map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]

G'day nottux,

Welcome to the Monastery.

I don't know what you intended. I suspect you're missing characters or have incorrect characters. What you've actually got here is:

1. 120*312-77728 -- an arithmetical expression
2. + -- added to
3. 2.22772.224792222 -- v-string (as a package name)
4. -> -- calling method
5. x -- x

Take a look at "perldata: Version Strings"; noting "If there are two or more dots in the literal, the leading v may be omitted."

Because by attempting to call a method on it you are treating it like a package name. What did you expect to happen?