Re^2: What's going on here?

Good catch about the version string but I would only say The -> operator is called on this string which interprets it as a class name. It has nothing to do with version string, e.g. 42->x does the same. I think.

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Re^3: What's going on here? by choroba (Cardinal) on Jul 13, 2023 at 09:53 UTC
Yes, 42 is turned into the string "42" which is interpreted as a class name. Basically, anything that's not a reference is stringified by the arrow operator. Update: See The Arrow Operator in perldoc. `map{substr$_->[0],$_->[1]\|\|0,1}[\\|\|{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^ARGV,3]`	[reply] [d/l]