in reply to Re: arithmetic in a regex ?
in thread arithmetic in a regex ?

one digit only.

so 9w10 is not valid, as 1 is not 9+1

13s4 => match would find "3s4"

3s44 => match would find "3s4"

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Re^3: arithmetic in a regex ?
by Corion (Patriarch) on Nov 13, 2023 at 08:43 UTC

    For the 9 cases, I would simply enumerate them:

    /( (0[a-z]1) |(1[a-z]2) |(2[a-z]3) |(3[a-z]4) |(4[a-z]5) |(5[a-z]6) |(6[a-z]7) |(7[a-z]8) |(8[a-z]9) )/x

    For further experimentation, I would write a test rig like the following to easily play with regular expressions and data and see how things work:

    #!perl use 5.020; use Test2::V0 '-no_srand' => 1; my @cases = ( # case, expected result, todo text ['13s4', '3s4' ], ['3s44', '3s4' ], ['0a1', '0a1' ], ['0a2', undef ], ); for my $case (@cases) { my( $line, $expected, $todo ) = @$case; my ($result) = $line =~ /( (0[a-z]1) |(1[a-z]2) |(2[a-z]3) |(3[a-z]4) |(4[a-z]5) |(5[a-z]6) |(6[a-z]7) |(7[a-z]8) |(8[a-z]9) )/x; my $t; if ($todo){ $t = todo( $todo ) }; is( $result, $expected, $line ); } done_testing;
      Which can be shortened to
      my $regex = join '|', map $_ . '[a-z]' . ($_ + 1), 0 .. 8; ... my ($result) = $line =~ /($regex)/;

      map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]
Re^3: arithmetic in a regex ?
by GrandFather (Saint) on Nov 13, 2023 at 08:45 UTC

    Not elegant, but fits the spec:

    /0.1|1.2|2.3|3.4|4.5|5.6|6.7|7.8|8.9|9.0/
    Optimising for fewest key strokes only makes sense transmitting to Pluto or beyond

      Thanks for your answers.

      Does this mean, arithmetic is not possible, in this case I have to generate a list of all possible cases ?

        You can run Perl code inside a regular expression (see perlre):

        #!perl use 5.020; use Test2::V0 '-no_srand' => 1; my @cases = ( # case, expected result, todo text ['13s4', '3s4' ], ['3s44', '3s4' ], ['0a1', '0a1' ], ['0a2', undef ], ); for my $case (@cases) { my( $line, $expected, $todo ) = @$case; my ($result) = $line =~ / ( (\d).(\d) # Capture the stuff (?(?{ $2+1 != $3 })(*FAIL)) # decide if things match our extende +d criteria )/x; my $t; if ($todo){ $t = todo( $todo ) }; is( $result, $expected, $line ); } done_testing;