in reply to Re^2: arithmetic in a regex ?
in thread arithmetic in a regex ?

For the 9 cases, I would simply enumerate them:

/( (0[a-z]1) |(1[a-z]2) |(2[a-z]3) |(3[a-z]4) |(4[a-z]5) |(5[a-z]6) |(6[a-z]7) |(7[a-z]8) |(8[a-z]9) )/x

For further experimentation, I would write a test rig like the following to easily play with regular expressions and data and see how things work:

#!perl use 5.020; use Test2::V0 '-no_srand' => 1; my @cases = ( # case, expected result, todo text ['13s4', '3s4' ], ['3s44', '3s4' ], ['0a1', '0a1' ], ['0a2', undef ], ); for my $case (@cases) { my( $line, $expected, $todo ) = @$case; my ($result) = $line =~ /( (0[a-z]1) |(1[a-z]2) |(2[a-z]3) |(3[a-z]4) |(4[a-z]5) |(5[a-z]6) |(6[a-z]7) |(7[a-z]8) |(8[a-z]9) )/x; my $t; if ($todo){ $t = todo( $todo ) }; is( $result, $expected, $line ); } done_testing;

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Re^4: arithmetic in a regex ?
by choroba (Cardinal) on Nov 13, 2023 at 10:16 UTC
    Which can be shortened to
    my $regex = join '|', map $_ . '[a-z]' . ($_ + 1), 0 .. 8; ... my ($result) = $line =~ /($regex)/;

    map{substr$_->[0],$_->[1]||0,1}[\*||{},3],[[]],[ref qr-1,-,-1],[{}],[sub{}^*ARGV,3]