Re^6: why is my for loop using modulo giving me a weird output

I used "use integer;" wouldn't this be correct? or should I add the int while doing the operation $i%5.

use strict;
use warnings;
use integer;
use constant number => 5;
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if I have to add this here, what situation am I avoiding?

I don't quite understand this

to chop off the fractional component for $quo

print "this is the quotient",int $i/5,"\n";
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Re^7: why is my for loop using modulo giving me a weird output by ww (Archbishop) on Jun 28, 2015 at 11:35 UTC
re "use integer" tells Perl "to use integer arithmetic instead of floating point" (see http://perldoc.perl.org/integer.html ) -- it's a pragma whereas marinersk's reference is to the function `int`, which you use correctly in your second code section (tho the output would look better if you included a space before the trailing quote on the text). UPDATE: s/correctly/ correctly assuming a value for $i greater than 5. If ($i <5) you'll get zero because int removes fractional the fractional part of a value `0.nnnn` / which will look a lot like `5%5`. (see -- on your own CLI -- `perldoc -f int`). Spirit of the Monastery	[reply] [d/l] [select]
Re^7: why is my for loop using modulo giving me a weird output by marinersk (Priest) on Jun 29, 2015 at 14:29 UTC
See for yourself: `#!/usr/bin/perl use strict; my $i = 1; my ($quo1, $rem1) = ($i/5, $i%5); #need to understand modulo print "Without int: Quotient = [$quo1], Remainder = [$rem1]\n"; my ($quo2, $rem2) = (int($i/5), $i%5); #modified to use int print " With int: Quotient = [$quo2], Remainder = [$rem2]\n"; exit; __END__` [download] Results: `D:\PerlMonks>modulo1.pl Without int: Quotient = [0.2], Remainder = [1] With int: Quotient = [0], Remainder = [1] D:\PerlMonks>` [download]	[reply] [d/l] [select]