I used "use integer;" wouldn't this be correct? or should I add the int while doing the operation $i%5.

use strict;
use warnings;
use integer;
use constant number => 5;
[download]

if I have to add this here, what situation am I avoiding?

I don't quite understand this

print "this is the quotient",int $i/5,"\n";
[download]

re "use integer" tells Perl "to use integer arithmetic instead of floating point" (see http://perldoc.perl.org/integer.html ) -- it's a pragma whereas marinersk's reference is to the function int, which you use correctly in your second code section (tho the output would look better if you included a space before the trailing quote on the text).

UPDATE: s/correctly/ correctly assuming a value for $i greater than 5. If ($i <5) you'll get zero because int removes fractional the fractional part of a value 0.nnnn / which will look a lot like 5%5. (see -- on your own CLI -- perldoc -f int).



Spirit of the Monastery

See for yourself:

#!/usr/bin/perl
use strict;

my $i = 1;
my ($quo1, $rem1) = ($i/5, $i%5); #need to understand modulo
print "Without int:  Quotient = [$quo1], Remainder = [$rem1]\n";

my ($quo2, $rem2) = (int($i/5), $i%5); #modified to use int
print "   With int:  Quotient = [$quo2], Remainder = [$rem2]\n";

exit;
__END__
[download]

Results:

D:\PerlMonks>modulo1.pl
Without int:  Quotient = [0.2], Remainder = [1]
   With int:  Quotient = [0], Remainder = [1]

D:\PerlMonks>
[download]