Re^4: why is my for loop using modulo giving me a weird output

totally mistaken on modulo.my bad..

I get it and thank you!

I guess , what I wanted to get out of this was the quotient NOT the remainder

so if I divide the number 20 by 5, I want the quotient 4. ok, let me try this again

then ,next step, is to write a program to find the smallest number that are evenly divided by all the given max_range numbers. ie: like 0-10.

use strict;
use warnings;
use integer;
use constant number => 5;
my %result;
for ( my $i=0; $i<=20 ;$i++){
    #my ($quo, $rem)= ($i/5, $i%5); #need to understand modulo 
    #print "this is quotient",$quo,"when this is divident $i \n";
    #print "this is remainder",$rem,"\n";
     if ($i%5==0 && $i!=0){
         print "this is the quotient",$i/5,"\n";
         print "this is the divident",$i,"\n";
         }
    }
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Re^5: why is my for loop using modulo giving me a weird output by marinersk (Priest) on Jun 28, 2015 at 08:50 UTC
I think you might benefit from the use of `int`in order to chop off the fractional component for `$quo`.	[reply] [d/l] [select]
Re^6: why is my for loop using modulo giving me a weird output by perlynewby (Scribe) on Jun 28, 2015 at 09:51 UTC
I used "use integer;" wouldn't this be correct? or should I add the int while doing the operation $i%5. `use strict; use warnings; use integer; use constant number => 5;` [download] if I have to add this here, what situation am I avoiding? I don't quite understand this to chop off the fractional component for $quo `print "this is the quotient",int $i/5,"\n";` [download]	[reply] [d/l] [select]
Re^7: why is my for loop using modulo giving me a weird output by ww (Archbishop) on Jun 28, 2015 at 11:35 UTC
re "use integer" tells Perl "to use integer arithmetic instead of floating point" (see http://perldoc.perl.org/integer.html ) -- it's a pragma whereas marinersk's reference is to the function `int`, which you use correctly in your second code section (tho the output would look better if you included a space before the trailing quote on the text). UPDATE: s/correctly/ correctly assuming a value for $i greater than 5. If ($i <5) you'll get zero because int removes fractional the fractional part of a value `0.nnnn` / which will look a lot like `5%5`. (see -- on your own CLI -- `perldoc -f int`). Spirit of the Monastery	[reply] [d/l] [select]
Re^7: why is my for loop using modulo giving me a weird output by marinersk (Priest) on Jun 29, 2015 at 14:29 UTC
See for yourself: `#!/usr/bin/perl use strict; my $i = 1; my ($quo1, $rem1) = ($i/5, $i%5); #need to understand modulo print "Without int: Quotient = [$quo1], Remainder = [$rem1]\n"; my ($quo2, $rem2) = (int($i/5), $i%5); #modified to use int print " With int: Quotient = [$quo2], Remainder = [$rem2]\n"; exit; __END__` [download] Results: `D:\PerlMonks>modulo1.pl Without int: Quotient = [0.2], Remainder = [1] With int: Quotient = [0], Remainder = [1] D:\PerlMonks>` [download]	[reply] [d/l] [select]