Re: Peek a hash without breaking iterator

I guess. What happens if you avoid each?

foreach my $key ( keys %hash ) {
    print qq($key => $hash{$key}\n);
    my %other_hash = %hash;
}
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If i run this, i don't get an infinite loop...

Regards, Karl

ŤThe Crux of the Biscuit is the Apostropheť

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Re^2: Peek a hash without breaking iterator by Anonymous Monk on Jun 20, 2016 at 21:16 UTC
If i run this, i don't get an infinite loop... Hurricup is writing a debugger, his debugger cannot be rewriting the users code while its running the code, the user isn't going to like that,	[reply]
Re^3: Peek a hash without breaking iterator by karlgoethebier (Abbot) on Jun 21, 2016 at 18:04 UTC
"Hurricup is writing a debugger...rewriting the users code..." Yes, sure. It interested me to see what happens, as i wrote. Or should i check out his plugin code (if available) and so on...? ŤThe Crux of the Biscuit is the Apostropheť	[reply]
Re^4: Peek a hash without breaking iterator by Anonymous Monk on Jun 21, 2016 at 23:03 UTC
See what happens is not relevant to the question the op asked, as pme explains Re: Peek a hash without breaking iterator	[reply]
Re^3: Peek a hash without breaking iterator by Anonymous Monk on Jun 21, 2016 at 18:47 UTC
"Hurricup is writing a debugger...rewriting the users code..." Yes, sure. It interested me to see what happens, as i wrote. Or should i check out his plugin code (if available) and so on...? ŤThe Crux of the Biscuit is the Apostropheť	[reply]