Re^2: Peek a hash without breaking iterator

If i run this, i don't get an infinite loop...

Hurricup is writing a debugger, his debugger cannot be rewriting the users code while its running the code, the user isn't going to like that,

Comment on Re^2: Peek a hash without breaking iterator

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Re^3: Peek a hash without breaking iterator by karlgoethebier (Abbot) on Jun 21, 2016 at 18:04 UTC
"Hurricup is writing a debugger...rewriting the users code..." Yes, sure. It interested me to see what happens, as i wrote. Or should i check out his plugin code (if available) and so on...? ŤThe Crux of the Biscuit is the Apostropheť	[reply]
Re^4: Peek a hash without breaking iterator by Anonymous Monk on Jun 21, 2016 at 23:03 UTC
See what happens is not relevant to the question the op asked, as pme explains Re: Peek a hash without breaking iterator	[reply]
Re^3: Peek a hash without breaking iterator by Anonymous Monk on Jun 21, 2016 at 18:47 UTC
"Hurricup is writing a debugger...rewriting the users code..." Yes, sure. It interested me to see what happens, as i wrote. Or should i check out his plugin code (if available) and so on...? ŤThe Crux of the Biscuit is the Apostropheť	[reply]