Re^3: how to declare a local *subname=sub{}?

> Main Q is why or how might I declare asub, or is *asub = sub{...} equivalent to sub asub {}

Almost equivalent, the prior has a runtime effect the latter only compile time.

See perlmod for phases of execution and do some experiments checking the availability of subs.

But I'm repeating myself now. ...

Cheers Rolf
_{(addicted to the Perl Programming Language and ☆☆☆☆ :)

Je suis Charlie!}

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Re^4: how to declare a local *subname=sub{}? by perl-diddler (Chaplain) on Oct 30, 2016 at 23:31 UTC
Ok, got that... but why doesn't the 'lvalue' "asub" need to be declared under strict?	[reply]
Re^5: how to declare a local *subname=sub{}? by LanX (Saint) on Oct 30, 2016 at 23:41 UTC
You are accessing a global symbol of the stash you don't need to declare hash elements of an existing hash either, do you? update You seem to think that local is declaring variables. That's totally wrong! Please read documentation and provided links. meta: This whole discussion is too XY for my taste, I'm out now. :) Cheers Rolf _{(addicted to the Perl Programming Language and ☆☆☆☆ :) Je suis Charlie!}	[reply]