Is skipping map() and chr() possible?

Thanks, both of you. The following produces the output I am expecting.

perl -e '$a=join("",map ({chr} 0xdf .. 0x0101)); print "$a\n";'

I guess there is no way to do the Unicode equivalent of 'A' .. 'Z' instead.

Is there some way to skip the map() or chr() functions?

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Re: Is skipping map() and chr() possible? by hippo (Archbishop) on Nov 16, 2017 at 09:33 UTC
Is there some way to skip the `map()` or `chr()` functions? Why would you want to skip them? Any why them but not join? Seems rather arbitrary. You'll need chr however you go about this and it is not a difficult fuction to understand. map can be avoided but you'll still need some sort of iterative/looping structure. eg: `perl -e 'print chr for 0xdf .. 0x0101, 0xa';` [download] That's with *nix EOL.	[reply] [d/l] [select]
Re: Is skipping map() and chr() possible? by Laurent_R (Canon) on Nov 16, 2017 at 08:19 UTC
Is there some way to skip the map() or chr() functions? Probably not. The `0xdf .. 0x0101` construct is just a range of numbers, you need, one way or another, to convert these numbers into characters.	[reply] [d/l]