Re: Using Regular Expressions to Simulate sprintf() function

Why use a regex at all?

# perl
$formatted = sprintf("%.2f", $unformatted);

# javascript, assuming it doesn't have a s?printf() function
formatted = Math.round(unformatted * 100) / 100;
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Comment on Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge Download Code

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Re: Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge by Incognito (Pilgrim) on Nov 06, 2001 at 06:59 UTC
This is a regex exercise. There are many ways to do this, but I'm doing a discussion with some coworkers on regular expressions... Remember, we're trying to 'simulate' the sprintf() without actually using it.	[reply]
Re: Re: Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge by Fastolfe (Vicar) on Nov 06, 2001 at 07:16 UTC
`s/(\d+(?:\.\d)?\|\d\.\d+)/sprintf("%.2f", $1)/eg; # :)` [download] I really can't think of a way to do this in a pure regex. You've got some logic in there (like the addition of zeros where there aren't enough) that I can't think of a way to express in a regular expression while accomplishing the rest of your requirements, short of using program logic like above. Even if there is a solution, I suspect it will make use of Perl's advanced regular expression features and would thus be unportable to JavaScript. I'm interested in seeing if there are any good responses, though.	[reply] [d/l]