Re: Re: Using Regular Expressions to Simulate sprintf() function

This is a regex exercise. There are many ways to do this, but I'm doing a discussion with some coworkers on regular expressions... Remember, we're trying to 'simulate' the sprintf() without actually using it.

Comment on Re: Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge

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Re: Re: Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge by Fastolfe (Vicar) on Nov 06, 2001 at 07:16 UTC
`s/(\d+(?:\.\d)?\|\d\.\d+)/sprintf("%.2f", $1)/eg; # :)` [download] I really can't think of a way to do this in a pure regex. You've got some logic in there (like the addition of zeros where there aren't enough) that I can't think of a way to express in a regular expression while accomplishing the rest of your requirements, short of using program logic like above. Even if there is a solution, I suspect it will make use of Perl's advanced regular expression features and would thus be unportable to JavaScript. I'm interested in seeing if there are any good responses, though.	[reply] [d/l]

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Re: Re: Re: Using Regular Expressions to Simulate sprintf() function - One Liner Challenge
by Fastolfe (Vicar) on Nov 06, 2001 at 07:16 UTC

s/(\d+(?:\.\d*)?|\d*\.\d+)/sprintf("%.2f", $1)/eg;    #  :)
[download]

I really can't think of a way to do this in a pure regex. You've got some logic in there (like the addition of zeros where there aren't enough) that I can't think of a way to express in a regular expression while accomplishing the rest of your requirements, short of using program logic like above. Even if there is a solution, I suspect it will make use of Perl's advanced regular expression features and would thus be unportable to JavaScript.

I'm interested in seeing if there are any good responses, though.

[reply]
[d/l]