in reply to parse filenames
ormy ($numbers) = $file =~ m/(\d{3})$/;
The latter is much faster then the former, but personal preference may dictate which you decide to use.my $numbers = substr ($file, -3, 3);
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Re: Re: parse filenames
by CukiMnstr (Deacon) on Apr 12, 2002 at 17:28 UTC | |
by ehdonhon (Curate) on Apr 12, 2002 at 19:12 UTC |