Re: dereferencing hash within a hash within an array

Looks like you need to rethink some things...

~~You're looping $i 1 through $x but you're also incrementing $x! When will this loop ever end?~~ (After carefully matching braces, I see that I was mistaken.)

Your data structure is very complex. You're trying to create an Array of Hashes of Arrays of Hashes? Or am I reading this wrong?

Comment on Re: dereferencing hash within a hash within an array

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Re: Re: dereferencing hash within a hash within an array by ihb (Deacon) on Jan 10, 2003 at 23:24 UTC
If I understand you correctly you expect `my $x = 10; for my $i (1 .. $x) { $x = 1; print $i; }` [download] to execute only once. That would be the case if the above was equivalent to `my $x = 10; for (my $i = 1; $i <= $x; $i++) { $x = 1; print $i; }` [download] , but it isn't. Recall that the non-C-style `for` (aka `foreach`) is a list iterator. `1 .. $x` is a list. Compare with `my @foo = 1 .. $x;` If you'd now do `foreach (@foo) { ... }` you wouldn't expect `foreach` to act any differently upon modification of `$x`. (Afaik `for (EXPR .. EXPR)` is nowadays optimized to not build a list, but that's irrelevant from a language point of view.) Hope I've helped, `ihb`	[reply] [d/l] [select]
Re: Re: dereferencing hash within a hash within an array by lpoht (Sexton) on Jan 11, 2003 at 01:41 UTC
The final data structure is an array of hashes. In each hash is another array of hashes (each hash having only one key/value pair).	[reply]