in reply to Re: 0**0
in thread 0**0

Except log(0) = -infinity; hence log(1)/log(0) = 0/-infinity, which is just another indeterminate.

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Re: Re: Re: 0**0
by buckaduck (Chaplain) on Jan 16, 2003 at 23:30 UTC 
    0/-infinity, which is just another indeterminate.

    Actually, 0/-infinity equals 0. It's not indeterminate. An indeterminate division would be something like infinity/infinity.

    buckaduck

[reply]
      Actually, 0/-infinity equals 0. It's not indeterminate.

      Actually, the limit of 0/x as x goes to -∞ is 0. Infinity is not a number, it's a concept.

      An indeterminate division would be something like infinity/infinity.

      The limit for x to ∞ of x/x is 1.

      — Arien

[reply]
        lim[x → ∞](x/x) = 1
        lim[x → ∞](2x/x) = 2

        Now which one do we take?

        Makeshifts last the longest.

[reply]

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