Re: Re: ignoring the first element of an array

The fourth way! (sounds like a book title:)

my $tmp = shift@derivative;
for my $well (@derivative) {
 # 
}
unshift @derivative, $tmp;
[download]

Comment on Re: Re: ignoring the first element of an array Download Code

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Re: Re: Re: ignoring the first element of an array by DaveH (Monk) on Feb 03, 2003 at 14:03 UTC
The destructive way... `for my $well (splice @derivative, 1, @derivative) { # }` [download] Cheers, -- Dave :-) $q=[split+qr,,,q,~swmi,.$,],+s.$.Em~w^,,.,s,.,$&&$$q[pos],eg,print	[reply] [d/l]
Re3: ignoring the first element of an array by Hofmator (Curate) on Feb 03, 2003 at 14:34 UTC
or the destructive and funky version of your code ;-) `for ( do {shift @derivative; @derivative} ) { # }` [download] -- Hofmator	[reply] [d/l]