in reply to sorting an array of hashes by the value of the keys

This will work for hashes with single keys
use Data::Dumper; my @aoh = ({doc1=>2345}, {doc2=>1234}, {doc3=>5678}, {doc4=>4567}); my @sorted_aoh = sort { (%$a)[1] <=> (%$b)[1] } @aoh; print Dumper \@sorted_aoh; __output__ $VAR1 = [ { 'doc2' => 1234 }, { 'doc1' => 2345 }, { 'doc4' => 4567 }, { 'doc3' => 5678 } ];

HTH

_________
broquaint

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Re: Re: sorting an array of hashes by the value of the keys
by diotalevi (Canon) on Jun 19, 2003 at 15:34 UTC

    I'll just expand on this so that it sorts on the key that starts with "doc" and ends with a number. This removes the "there must be only one key" requirement.

    my @sorted_aoh = sort { (map /^doc(\d+)/ ? 0+$1 : (), keys(%$a))[0] <=> (map /^doc(\d+)/ ? 0+$1 : (), keys(%$b))[0] } @aoh;

    That happens to be suboptimal because every comparison is doing a potentially expensive operation to each hash. An improvement would be to use a Guttman-Rossler transform and then you get something really slick.

    my @sorted_aoh = map $aoh[ substr $_, 5 ], sort map { # Retrieve the document number my $doc_key = (map /^doc(\d+)$/ ? 0 + $1 : (), keys %{$aoh[$_]})[0 +]; # Return the document number, a null and the original array index pack( 'N', $doc_key ) . "\0" . $_; } 0 .. $#aoh