in reply to Re: Re: $1 trap
in thread $1 trap

The OP's code was actually returning "yes" if $1 contained a true value. So, the following would've returned "no":

chg("w0rd", qr/(\d)/); # that's a zero, not capital O

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Re: Re3: $1 trap
by Chady (Priest) on Aug 11, 2003 at 05:43 UTC
    NO.

    This would return "yes", because the regex will match, and thus will return true, even if there is no parens in the regex.

    That's why this works: 
    $_ = "something blah blah";
if (/something/) {
     print "Ok";
}

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      NO. This would return "no", because he's not only comparing the
      result of the regex, but also the value of the submatch:

      "w0rd" =~ /(\d)/ && $1 ? print"Yes": print"no";

      The regex matches, so $1 becomes 0. This makes the condition:

      (true) && 0 ? print"Yes": print"no";

      Which evaluates to false.

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