in reply to Re3: $1 trap
in thread $1 trap

NO.

This would return "yes", because the regex will match, and thus will return true, even if there is no parens in the regex.

That's why this works: 
$_ = "something blah blah";
if (/something/) {
     print "Ok";
}

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Re: Re: Re3: $1 trap
by Crackers2 (Parson) on Aug 11, 2003 at 16:46 UTC
    NO. This would return "no", because he's not only comparing the
    result of the regex, but also the value of the submatch:

    "w0rd" =~ /(\d)/ && $1 ? print"Yes": print"no";

    The regex matches, so $1 becomes 0. This makes the condition:

    (true) && 0 ? print"Yes": print"no";

    Which evaluates to false.

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