Re: A little C code converted to Perl *HELP*

Oh, I almost missed that little part at the end with the sprintf...

   DWORD generated_check=(rand()<<16) | rand();
   char gcheck[64];
   sprintf(gcheck, "%x", generated_check);
[download]

My C, as I said, is marginal, but if this is doing what I think it's doing, ...

   $gcheck = printf "%x", ((rand() << 16) | rand());
[download]

I'm assuming here that the C << operator is a left shift just like in Perl, but that's a wild guess. I'm also assuming that rand with no args in C does the same thing as in Perl, which is also a guess. Like I said, my knowledge of C leaves something to be desired. I know what the Perl code does. (It prints "0" every time.) I'm guessing at the C code. Probably guessing wrong.

$;=sub{$/};@;=map{my($a,$b)=($_,$;);$;=sub{$a.$b->()}}
split//,".rekcah lreP rehtona tsuJ";$\=$ ;->();print$/
[download]

Comment on Re: A little C code converted to Perl HELP Select or Download Code

Replies are listed 'Best First'.
Re2 (rand() in C): A little C code converted to Perl HELP by bbfu (Curate) on Nov 03, 2003 at 17:54 UTC
The rand function in C returns a random integer. The OP's C code seems to assume 16 bit integers, so that's a max of 65535 (or 32767 to -32768, IIRC). So, I think the equivalent Perl code would be something like: `$gcheck = sprintf "%x", ((int(rand(65536)) << 16) \| int(rand(65536)));` bbfu Black flowers blossom Fearless on my breath	[reply] [d/l]
Re: Re: A little C code converted to Perl HELP by regnab (Initiate) on Nov 03, 2003 at 04:49 UTC
okay, great many thanks mate!! (if someone thinks this wasnt correct, pls reply another solution) Thanks again mate!!! :))	[reply]
Re: Re: A little C code converted to Perl HELP by regnab (Initiate) on Nov 03, 2003 at 04:53 UTC
hmmm cant get that line working you gave me .. always give me 0 , or 1 ... i think somethings wrong there :( hmmmm any solution code? many thx	[reply]
Re: A little C code converted to Perl HELP by jonadab (Parson) on Nov 03, 2003 at 05:00 UTC
cant get that line working you gave me .. always give me 0 , or 1 ... Yes, of course. Should almost always be 0, I think. (rand with no arguments produces a number between 0 and 1; you're left-shifting that a whole bunch and then evaluating it in integer context.) The question is, what did you want it to do? If you can tell me what the C code does, we can save all this guesswork and get straight to a _working_ example. Even a really vague explanation in English would be preferable to C code. I tried reading the C code, but I had to make some assumptions about things I wasn't sure about, and since you're unhappy with my translation, it's apparent that some of my assumptions were wrong. In particular, I suspect I was wrong about what rand with no args does in C. If I needed to know that sort of thing, I'd be hanging out in comp.lang.c or someplace (or else committing ritual suicide). `$;=sub{$/};@;=map{my($a,$b)=($_,$;);$;=sub{$a.$b->()}} split//,".rekcah lreP rehtona tsuJ";$\=$ ;->();print$/` [download]	[reply] [d/l]