cant get that line working you gave
me .. always give me 0 , or 1 ...
Yes, of course. Should almost always be 0, I think.
(rand with no arguments produces a number between 0
and 1; you're left-shifting that a whole bunch and
then evaluating it in integer context.)
The question is, what did you *want* it to do?
If you can tell me what the C code *does*, we can
save all this guesswork and get straight to a
_working_ example. Even a really *vague* explanation
in English would be preferable to C code. I tried
reading the C code, but I had to make some assumptions
about things I wasn't sure about, and since you're
unhappy with my translation, it's apparent that some
of my assumptions were wrong. In particular, I
suspect I was wrong about what rand with no args
does in C. If I needed to know that sort of thing,
I'd be hanging out in comp.lang.c or someplace (or
else committing ritual suicide).
$;=sub{$/};@;=map{my($a,$b)=($_,$;);$;=sub{$a.$b->()}}
split//,".rekcah lreP rehtona tsuJ";$\=$ ;->();print$/
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