Re: Reg expression on day

An alternate way of doing this might be to break out your MM/DD/YYYY into seperate chunks (ie $MM = month, $DD = day, and $YYYY = year), then take the day variable and add zero to it. Then put it all back together again. This way you could manipulate the date if you needed to.

($MM, $DD, $YYYY) = split(/,"$date");
$MM=$MM+0;
$DD=$DD+0;
$date=$MM."/".$DD."/".$YYYY;
[download]

Please forgive me if my split syntax is incorrect. I don't have an example in front of me. Anyway, I am just providing an alternate methodry. Although if you absolutely need to use a regex or want to get better at using them, this definitely won't help you!

Have fun!

UPDATE: Thanks flounder99 for the correction, I thought that I was missing something!

Paulster2

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Re: Re: Reg expression on day by flounder99 (Friar) on Dec 23, 2003 at 18:04 UTC
Please forgive me if my split syntax is incorrect All you need is to quote your slash: `split('/',"$date")` [download] I was thinking of something similar: `s!(\d+)/(\d+)!($1+0).'/'.($2+0)!e` [download] -- flounder	[reply] [d/l] [select]
Re: Re: Reg expression on day by trammell (Priest) on Dec 23, 2003 at 18:09 UTC
Sure, and it cleans up a bit: `$date = join "/", map $_+0, split m[/], $date;` Not sure if I like the idea of stripping those zeroes though. Probably better to store the date in a saner format (Epoch seconds maybe?), then use POSIX::strftime() to generate the desired date format.	[reply] [d/l]