in reply to RE: Re: dsfddf
in thread Reaped: dsfddf
You don't need the my $lefthand= (); line since you never use a scalar named "lefthand". $lefthand{dsfddf} accesses the hash. You use "$" because you are getting a scalar back, but it has nothing to do with the variable $lefthand.
- tye (but my friends call me "Tye")
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