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Re: dsfddf
by d4vis (Chaplain) on Sep 15, 2000 at 20:27 UTC
    I'm not sure exactly what you're trying to do, but try: 
    #!/usr/bin/perl -w
use strict;
my %lefthand= qw(dsfddf asdfsfda);

print $lefthand {dsfddf};

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    Hope this helps. ;)

    ~novice d4vis
    #!/usr/bin/fnord
    Editied Version...Thanks Tye

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[d/l]
      Um... Global symbol "%lefthand" requires explicit package name at - line 1.
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[d/l]
      Heh...well, it was just a joke but the reply got me to read the docs on use strict, which I (obviously) hadn't really used much. So is;
      #!/usr/bin/perl -w
use strict;
my %lefthand= qw(dsfddf asdfsfda);
my $lefthand=();
print $lefthand {dsfddf};

      [download]

      the proper usage?
      Thanks for the tip.

      ~novice d4vis
      #!/usr/bin/fnord

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[d/l]
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        You don't need the my $lefthand= (); line since you never use a scalar named "lefthand". $lefthand{dsfddf} accesses the hash. You use "$" because you are getting a scalar back, but it has nothing to do with the variable $lefthand.

                - tye (but my friends call me "Tye")
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