Re: dsfddf

I'm not sure exactly what you're trying to do, but try:

#!/usr/bin/perl -w
use strict;
my %lefthand= qw(dsfddf asdfsfda);

print $lefthand {dsfddf};
[download]

Hope this helps. ;)

~novice d4vis
#!/usr/bin/fnord
Editied Version...Thanks Tye

Comment on Re: dsfddf Download Code

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RE: Re: dsfddf by Anonymous Monk on Sep 15, 2000 at 22:44 UTC
Um... `Global symbol "%lefthand" requires explicit package name at - line 1.`	[reply] [d/l]
RE: Re: dsfddf by d4vis (Chaplain) on Sep 16, 2000 at 01:25 UTC
Heh...well, it was just a joke but the reply got me to read the docs on `use strict`, which I (obviously) hadn't really used much. So is; `#!/usr/bin/perl -w use strict; my %lefthand= qw(dsfddf asdfsfda); my $lefthand=(); print $lefthand {dsfddf};` [download] the proper usage? Thanks for the tip. ~novice d4vis #!/usr/bin/fnord	[reply] [d/l] [select]
RE: RE: Re: dsfddf by tye (Sage) on Sep 16, 2000 at 03:02 UTC
You don't need the `my $lefthand= ();` line since you never use a scalar named "lefthand". `$lefthand{dsfddf}` accesses the hash. You use "$" because you are getting a scalar back, but it has nothing to do with the variable `$lefthand`. - tye (but my friends call me "Tye")	[reply] [d/l] [select]