You don't even need the exists (assuming you don't have a weird freeform data structure):

if (Hash{$neededVal} and $Hash{$neededVal}{param1} and
    $Hash{$neededVal}{param1}{key1} > 4) {

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In reply to Re^2: Checking if hash value exists without implicitly defining it by Anonymous Monk
in thread Checking if hash value exists without implicitly defining it by Doctrin

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