> Is it possible to combine different types of rules in this algorithm?

Well not A > B is equivalent to B >= A.

But the B == A part - i.e. B and A belong to the same phase - must be ignored, otherwise one risks that A comes after B in the unsorted output of a phase.

So translating to B > A should be safe, w/o loss of solutions.

Just modify the parser to translate different rules accordingly.

HTH! =)

Cheers Rolf

( addicted to the Perl Programming Language)

In reply to Re^3: Sorting by dependencies by LanX
in thread Sorting by dependencies by Anonymous Monk

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