Whenever you do $foo++, the interpreter is converting $foo to an integer, whether it was a string or a float before, then incrementing it.

Sorry to disagree, but Perl won't do this.

How do you convert a string like 'perlhacker' to an integer?
But Perl is able to increment 'perlhacker' to 'perlhackes', this is some magic built into the increment operator.

In reply to Re: Re3: alphanumeric autoincrement? by busunsl
in thread alphanumeric autoincrement? by HK

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