I think the first and second $x would be 6 actually, due to the prepend happening on the second $x.

Here are the steps in order:

1. ++$x: All $x are now 6.

2. 6 + 6 + 6

3. $x++: All $x are now 7.

4. $x = 18: The value from the 6 + 6 + 6 is assigned to $x.

In reply to Re: question 1st - undefined behaviour by Riales
in thread question 1st - undefined behaviour by rumos2

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