G'day WingedKnight,

Welcome to the Monastery.

When in doubt, it's often a good idea to find out how Perl is seeing your code with B::Deparse. 

$ perl -MO=Deparse,-p -e 'print "foo, " . (1 ? "yes" : "no") . " bar";
+'
print('foo, yes bar');
-e syntax OK

[download]
$ perl -MO=Deparse,-p -e 'print (1 ? "yes" : "no") . " bar";'
(print('yes') . ' bar');
-e syntax OK

[download]
"Why isn't " bar" getting appended to the output in the second case?"

Because it's getting appended to the return value from print. 

$ perl -e '$x = print "foo, " . (1 ? "yes" : "no") . " bar"; print "\n
+$x\n"'
foo, yes bar
1

[download]
$ perl -e '$x = print (1 ? "yes" : "no") . " bar"; print "\n$x\n"'
yes
1 bar

[download]

Of course, you should start all your code with: 

use strict;
use warnings;

[download]

In this case, you would have received warnings: 

$ perl -e 'use strict; use warnings; print (1 ? "yes" : "no") . " bar"
+;'
print (...) interpreted as function at -e line 1.
Useless use of concatenation (.) or string in void context at -e line 
+1.
yes

[download]

See "perlintro: Safety net".

— Ken

In reply to Re: Strange interaction between print and the ternary conditional operator by kcott
in thread Strange interaction between print and the ternary conditional operator by WingedKnight

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